10x^2-70x+12=0

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Solution for 10x^2-70x+12=0 equation:



10x^2-70x+12=0
a = 10; b = -70; c = +12;
Δ = b2-4ac
Δ = -702-4·10·12
Δ = 4420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4420}=\sqrt{4*1105}=\sqrt{4}*\sqrt{1105}=2\sqrt{1105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1105}}{2*10}=\frac{70-2\sqrt{1105}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1105}}{2*10}=\frac{70+2\sqrt{1105}}{20} $

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